String no print c++ -

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i'm new in programming, have big code, when try print data never prints string variable, can help? use "goto" practicall reassons.

   #include <iostream>     #include <string>     #include <cstdlib>     using namespace std;      class producto     {     public:         int id;         string nombre;         string descripcion;         int precio;         void registrar();         void ver();     };     void producto::registrar()     {         cout << "codigo:" << endl;         cin >> id;         cin.ignore();         cout << "nombre del producto:" << endl;         getline(cin, nombre);         cout << "descripcion del producto:" << endl;         getline(cin, descripcion);         cout << "precio:" << endl;         cin >> precio;      }     void producto::ver()     {         cout << "id del producto:";         cout << id << endl;         cout << "nombre del producto:" << endl;         cout << nombre;         cout << "descripcion del producto:";         cout << descripcion<<endl;         cout << "precio:";         cout << "$" << precio << endl;      } int main() { menu1:     int menu;     producto cosa;     cout << "************************" << endl;     cout << "1.- registrar producto" << endl;     cout << "2.- ver producto" << endl;     cout << "************************" << endl;     cin >> menu;     cin.ignore();     switch (menu)     {     case 1:         cout << "ingrese producto nuevo:\npresione enter para continuar" << endl;         cin.ignore();         system("cls");         cosa.registrar();         cin.ignore();         break;     case 2:         cosa.ver();         cout << "presione enter para regresar al menu principal." << endl;         cin.ignore();         break;      }     goto menu1;     return 0; }

edit here int main

the use of goto not recommended , considered bad practice beginner. if begining in c++, following best practice best way begin. goto supported in c/c++ backward compatibility.

for issue try use loop instead of goto. 

int main() {        //condition show menu or exit     bool bcontinue = true;     producto cosa;      do{          int menu;         cout << "************************" << endl;         cout << "1.- registrar producto" << endl;         cout << "2.- ver producto" << endl;         cout << "3.- exit" << endl;         cout << "************************" << endl;         cin >> menu;         cin.ignore();          switch (menu)         {         case 1:             cout << "ingrese producto nuevo:\npresione enter para continuar" << endl;             cin.ignore();             system("cls");             cosa.registrar();             cin.ignore();             break;         case 2:             cosa.ver();             cout << "presione enter para regresar al menu principal." << endl;             cin.ignore();             break;         case 3:             bcontinue = false;             break;         }      }while(bcontinue)     return 0; }

like way, issue fixed , learn better way it.


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