c# - How Do I make a Dynamically Compiled Class emit to a DLL -

i have data uses create program. purposes of example generated code:

using system;  namespace mynamespace {     public class builtprogram{         public bool eval(int x, int y, int z, out int ret) {             console.writeline("test");             ret = x + y + z;             return true;         }         } } 

the code use generate following:

var factory = new programfactory(tree); var newprogram = factory.getcompiledprogram();  // program parsing code... syntaxtree programsyntaxtree = syntaxtree.parsetext(newprogram); var outputfile = "compiled.dll"; var compilation = compilation.create(outputfile,     options: new compilationoptions(outputkind.dynamicallylinkedlibrary),     syntaxtrees: new[] { programsyntaxtree } );  filestream file; using (file = new filestream(outputfile, filemode.create)) {     emitresult result = compilation.emit(file); } // code breaks: assembly assembly = assembly.loadfile(file.name);  type type = assembly.gettype("builtprogram"); var obj = activator.createinstance(type); int ret = 0; type.invokemember("eval",     bindingflags.default | bindingflags.invokemethod,     null,     obj,     args: new[] {         (object)5,         (object)10,         (object)2,         ret     } ); 

it breaks on assembly line because says doesn't have assembly manifest, @ "compiled.dll" , there no data in it. doing wrong?

you have add reference mscorlib.

this make work:

 var compilation = compilation.create(outputfile,                 options: new compilationoptions(outputkind.dynamicallylinkedlibrary),                 syntaxtrees: new[] { programsyntaxtree },                 references: new [] { new metadatafilereference(typeof(object).assembly.location) }         ); 

while accesing type, add namespace.

type type = assembly.gettype("mynamespace.builtprogram"); 

you may have difficulty getting out parameter value. see this.