android - Custom listview selector / drawable dimensions? -

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is there way can set listview selector custom drawable occupies portion of item view? have made drawable rectangle , set selector, i'm having difficult time getting size properly. picture shows have (1) , desired effect (2).

got - decided set selector drawable shows border on 1 side, , messed around insets no avail (for reason top , bottom not working properly). made layer list , offset top layer right few dp.

<?xml version="1.0" encoding="utf-8"?> <layer-list xmlns:android="http://schemas.android.com/apk/res/android">     <item android:top="0dp" android:left="0dp" android:bottom="0dp" android:right="0dp">         <shape android:shape="rectangle">             <solid android:color="@color/coloraccent"/>         </shape>     </item>     <item android:top="0dp" android:left="5dp" android:bottom="0dp" android:right="0dp">         <shape android:shape="rectangle">             <solid android:color="#ffffff"/>         </shape>     </item> </layer-list>

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