mysql - php script only display one row of data instead of many in android studio -

i ask how can display many rows of data instead of 1 row. following code display 1 row of record instead of multiple records available. i'm using mysqli_prepare statements here. or problem on android studio coding? application implemented login function , coding below.

<?php $host="db_host"; $user="db_user"; $password="db_password"; $db="db_name";  $con = mysqli_connect($host,$user,$password,$db);  $parentic=$_post["parentic"]; $password=$_post["password"];  $selectquery = mysqli_prepare($con, "select parents_data.name, student_list.studname, student_list.studic, student_list.form,student_list.class,discipline_record.date,discipline_record.rulescode, discipline_record.typesofmistakes,discipline_record.punishment discipline_record left join student_list on discipline_record.studic = student_list.studic left join parents_data on student_list.parentic = parents_data.parentic parents_data.parentic = ? , parents_data.password = ? "); mysqli_stmt_bind_param ($selectquery, "ss", $parentic, $password); mysqli_stmt_execute($selectquery);  mysqli_stmt_store_result($selectquery); mysqli_stmt_bind_result($selectquery,$name,$studname,$studic,$form,$classs,$ddate,$code,$mistakes,$punishment);  $user = array();    while(mysqli_stmt_fetch($selectquery)) {     $user[name]=$name;     $user[studname]=$studname;     $user[studic] = $studic;     $user[form]=$form;     $user[classs]=$classs;     $user[ddate]=$ddate;     $user[code]=$code;     $user[mistakes]=$mistakes;     $user[punishment]=$punishment;               }      echo json_encode($user);      mysqli_stmt_close($selectquery);   mysqli_close($con);  ?>                           

i go that:

$usergroup = array(); $user = array();  while(mysqli_stmt_fetch($selectquery)) {     $user[name]=$name;     $user[studname]=$studname;     $user[studic] = $studic;     $user[form]=$form;     $user[classs]=$classs;     $user[ddate]=$ddate;     $user[code]=$code;     $user[mistakes]=$mistakes;     $user[punishment]=$punishment;  array_push($usergroup,$user);               }  echo json_encode($usergroup);