Writing to a resource in Java? -

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• how can app use files inside jar read , write? 5 answers

i trying save data file on computer using class.getresource() method. problem returns url. cannot find way write file using url. here code have far:

url = getclass().getresource("save.txt"); urlconnection urlconn = url.openconnection(); outputstream os = urlconn.getoutputstream(); outputstreamwriter isr = new outputstreamwriter(os); buffer = new bufferedwriter(isr); 

when run java.net.unknownserviceexception: protocol doesn't support output error. not sure do.

you can't write resource that. it's meant read only.

on other hand, can find out path of resource file. 1 of methods be:

finding out path of resource

public static file findclassoriginfile( class cls ){     // try find class file.     try {         final url url = cls.getclassloader().getresource( cls.getname().replace('.', '/') + ".class");         final file file = new file( url.getfile() ); // tostring()         if( file.exists() )             return file;     }     catch( exception ex ) { }      // method 2     try {         url url = cls.getprotectiondomain().getcodesource().getlocation();         final file file = new file( url.getfile() ); // tostring()         if( file.exists() )             return file;     }     catch( exception ex ) { }      return null; } 

the method above finds file class, may changed resource well.

what recommend use resource default, copy out of classpath working directory , save there.

copying resource dir

public static void copyresourcetodir( class cls, string name, file dir ) throws ioexception {     string packagedir = cls.getpackage().getname().replace( '.', '/' );     string path = "/" + packagedir + "/" + name;     inputstream = groovyclassloader.class.getresourceasstream( path );     if( == null ) {         throw new illegalargumentexception( "resource not found: " + packagedir );     }     fileutils.copyinputstreamtofile( is, new file( dir, name ) ); }